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+1 vote
26.1k views
in Chemical thermodynamics by (64.8k points)

Calculate the enthalpy of the reaction H2C = CH2 (g) +H2 (g) →CH3 - CH3 (g) The bond energies of C - H.C -C.C = C and H -H are 99,83,147 and 104 kcal respectively

1 Answer

+1 vote
by (58.4k points)
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Best answer

The reaction is:

∆H = ?

∆H= Sum of bond energies of reactants – Sum of bond energies of products

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