Question

For which of the following change ∆ ≠∆ H E?

(A) H₂(g) +I₂ (g)→ 2HI (g)

(B) HCl (aq) +NaOH (aq)→ NaCl (aq) +H₂O(I)

(C) C (S) +O₂ (g) → CO₂ (g)

(D)N₂ (g) +3H₂(g) →2NH₃(g)

 

Answer 1

Correct option (D)N₂ (g) +3H₂(g) →2NH₃(g)

Explanation:

 ∆H = ∆E + ∆ngT

Case–I = ∆n_g = 2 – 1 –1 = 0

Case–II = ∆n_g = 0 – 0 = 0

Case–III = ∆n_g = 1 – 1 = 0

Case–IV = ∆n_g = 2 – 3 – 1 = –2 ≠ 0 

∴ In option (D) ∆H = ∆E