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 When 2 moles of C2H6 (g) are completely burnt 3120 kJ of heat is liberated. Calculate the enthalpy of formation, of C2H6 (g). Given ∆fH for CO2 (g) and H2O (l) are – 395 &286 kJ respectively.

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2C2 H6 + 7O2 → 4CO2 + 6H2O

∆Hcomb = ∆H for reactants – ∆Hf products 

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