Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
6.5k views
in Mathematics by (50.4k points)

Determine the range of the following expressions. (x2 + x + 1)/(x2 - x + 1)

1 Answer

+1 vote
by (54.8k points)
selected by
 
Best answer

Let y = (x2 + x + 1)/(x2 - x + 1)

⇒ x2y – xy + y = x2 + x + 1

⇒ x2y – xy + y – x2 – x – 1 = 0

⇒ x2(y – 1) – x(y + 1) + (y – 1) = 0

x is real ⇒ b2 – 4ac ≥ 0

⇒ (y + 1)2 – 4(y – 1)2 ≥ 0

⇒ (y + 1)2 – (2y – 2)2 ≥ 0

⇒ (y + 1 + 2y – 2) (y + 1 – 2y + 2) ≥ 0

⇒ (3y – 1) (–y + 3) ≥ 0

⇒ –(3y – 1) (y – 3) ≥ 0

a = coeff. of y2 = –3 < 0.,But

The expression ≥ 0

⇒ y lies between 1/3 and 3

∴ The range of (x2 + x + 1)/(x2 - x + 1) is [1/3, 3]

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...