Question

Find dy/dx, if y = (tanx)^{cot x} + (cotx)^tanx

Answer 1

Given y = (tanx)^{cot x} + (cot x)^tanx

⇒ y = e^{log(tanx)cot x} + e^{log(cot x)tanx}

⇒ y = e^{cot x log(tanx)} + e^{tanx log(cot x)}