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in Limit, continuity and differentiability by (50.4k points)

If y = tan–1x, prove that (1 + x2)y2 + 2xy1 = 0

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Best answer

Given y = tan–1x

⇒ dy/dx = 1/(1 + x2)

⇒ (1 + x2)(dy/dx)  = 1

⇒ (1 + x2)(d2y/dx2) + 2x(dy/dx) = 0

⇒ (1 + x2)y2 + 2xy1 = 0

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