Question

Find the number of tangents to the curve y² – 2x² – 4y + 8 = 0 that pass through (1, 2).

Answer 1

Given curve is y² – 2x² – 4y + 8 = 0

Now, 4 – 2.1 – 8 + 8 = 4 – 2 = 2 > 0

So, the point lies outside of the curve.

Thus, the number of tangents to the curve is 2.