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in Limit, continuity and differentiability by (41.7k points)
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Find the least value of f(x) = (x3 + x + 2)/x , x > 0

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We have, f(x) = (x3 + x + 2)/x , x > 0

 f(x) = x2 + 2/x + 1

 f(x) = (x2 + 1/x + 1/x)

 f(x) ≥ 3 + 1 = 4

Hence, the min value of f(x) is 4.

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