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Find the least value of f(x) = 2cosx + sec^2x, x ∈ [ 0, π/2)

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in Limit, continuity and differentiability by (41.7k points)

Find the least value of f(x) = 2cosx + sec2x, x ∈ [ 0, π/2) 

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We have f(x) = 2cos x + sec2x

⇒ f(x) = cos x + cos x + sec2x

⇒ f(x) = cos x + cos x + sec2x ≥ 3

Hence, the min value of f(x) is 3.

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