We have f(x) = |x| – |x3 – 1|
![](https://www.sarthaks.com/?qa=blob&qa_blobid=14936029584504591688)
Now, for max or min, f¢(x) = 0 gives
x = –√(2/3), 0, √(2/3)
Thus, the function provide us the point of local max are x = – √(2/3), √(2/3)
when x = – √(2/3), then y = 1/3√2/3 –1
when x = √2/3 , then y = 1/3 √(2/3) + 1
Thus, the points of local maximum are
P( –√(2/3), 1/3√(2/3) – 1) and Q(√(2/3), 1/3√(2/3) + 1)
Hence, the distance between P and Q is
![](https://www.sarthaks.com/?qa=blob&qa_blobid=15663123807289462808)