Let f'(x) = (x – 1)(x – 2)(x – 3)
⇒ f'(x) = x3 – 6x2 + 11x – 6
⇒ f(x) = x4/4 – 6(x3/3) + 11(x2/2) – 6x + b
⇒ f(x) = x4/4 – 2x3 + 11/2x2 – 6x + b
f(0) = 2 gives b = 2
Hence, the polynomial function is
f(x) = x4/4 – 2x3 + (11/2)x2 – 6x + 2
⇒ f(x) = 1/4(x4 – 8x3 + 44x2 – 24x + 8)