Question

Evaluate the following:

(A) tan^-1 (-1)

(B) cot^-1(-1)

(C) sin^-1 (-√3/2)

Answer 1

(A) tan(-π/4) = -1

Hence,

tan^-1(-1) = - π/4{since(-π/4)  ∈ range of tan^-1x}

(B) cot(3π/4) = - 1

Hence,

cot^-1(-1) = 3π/4{since(3π/4) ∈ range of cot^-1x}

(C) sin(-π/3) = -√3/2

Hence,

sin^-1(-√3/2) = π/3{since (-π/3) ∈ range of sin^-1x}