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in Trigonometry by (41.7k points)

If ∑sin-1xi for i ∈ [i=1, 2n] = n, then ∑xi for i ∈ [i=1, 2n] is

(A) n

(B) 2n

(C) n(n +1)/2

(D) None of these

1 Answer

+1 vote
by (41.5k points)
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Best answer

Correct option (B) 2n

Explanation:

Given sin-1x1 + sin-1x2 + … + sin-1x2n = nπ

which is possible only if

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