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A particle has an initial velocity of 9 m/s due east and a constant acceleration of 2 m/s2 due west. The distance covered by the particle in the fifth second of its motion is 

(a) 0 

(b) 0.5 m 

(c) 2 m 

(d) none of these

1 Answer

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Best answer

Correct answer is: (b) 0.5 m

Here, u = 9 m/s, a = - 2 m/s2. For v = 0, t = 4.5 s. The required interval is from t = 4 s to t = 5 s. This includes the turning point. Hence, find displacements for t = 4 s, t = 4.5 s, t = 5 s.

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