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If f(x) = ∫cos √t dt for t ∈ [1/x^2,x^2], the value of f'(1) is ...

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If f(x) = ∫cos √t dt for t ∈ [1/x2,x2], the value of f'(1) is ...

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1 Answer

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Best answer

Given, 

= 2(cos(1)) + 2(cos(1)) 

= 4(cos(1))

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