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X and Y are two sets and f: X → Y. If {f(c) = y; c ⊂ X, y ⊂ Y} and {f −1(d) = x; d ⊂ Y, x ⊂ X}, then the true statement is

(A)  f[f −1(b)] = b

(B)  f −1[f(a)] = a 

(C)  f[f −1(b)] = b, b ⊂ y

(D)  f −1[f(a)] = a, a ⊂ x

1 Answer

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Best answer

Correct option (D) f −1[f(a)] = a, a ⊂ x

Explanation :

The given data is shown in Fig. Since f-1 (d) = x, we get Now, if  a ⊂ x, f(a) ⊂ d, we get f –1[f(a)] = a.

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