Question

Establish the relationship between electric field intensity and electric potential.

Answer 1

Consider two points A and B with small distance dr between them. If q is the change placed at B and move toward A then,

At point B, force on q = qE

At point A,force on q = qE

The potential difference between two points A and B will be

V_B-V_A- dv = W(AB)lq V(AB)=F.dr.cos 180/q

-ve sign indicates that potential decreases in the direction of electric field.