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If in a ∆ABC, sin^2A + sin^2B + sin^2C = 2, then the triangle is always

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If in a ∆ABC, sin2A + sin2B + sin2C = 2, then the triangle is always

(A) Isosceles triangle

(B) Right angled 

(C) Acute angled 

(D) Obtuse angled

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1 Answer

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Correct option   (B) Right angled

in2 A + sin2 B + sin2C = 2 ⇒ 2 cos A cos B cos C = 0

⇒ Either A = 90° or B = 90° or C = 90° 

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