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If sinθ, cosθ and tan θ are in GP, then cot5 θ cot2θ − is equal to

(A)  cosec2 θ

(B)   cosecθ

(C)  1 

(D)  0

1 Answer

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Best answer

Correct option (C)  1 

Given sin θ , cos θ and tan q are in GP. This means

cos2  θ  = sin2 θ /cos θ ⇒ sin2θ = cos3θ ⇒ cosec ⇒ = cot3 θ

Now,

cot6 θ - cot2 θ = cosec2  θ cot2 θ = 1 

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