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If tanθ = n tan f, then the maximum value of tan^2 (θ - ϕ) is equal to

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If tanθ = n tan ϕ, then the maximum value of tan2 (θ - ϕ) is equal to

(A)   (n - 1)2/4n

(B)   (n + 1)2/4n

(C)  (n + 1)/2n

(D)  (n - 1)/2n

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1 Answer

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Best answer

Correct option (A)   (n - 1)2/4n

 We have

Therefore, maximum value of tan2(θ - ϕ) is (n - 1)2/4n.

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