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The number of solution of equation 8[x^2 − x] + 4[x] = 13 + 12[sinx]

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The number of solution of equation 8[x2 − x] + 4[x] = 13 + 12[sinx]

(A)  0 

(B)  2 

(C)  4 

(D)  6 

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1 Answer

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Best answer

Correct option (A)  0 

LHS is an even number and RHS is an odd number always. Hence, number of solution is 0.

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