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in Physics by (50.3k points)

A long, straight, hollow conductor (tube) carrying a current has two sections A and C of unequal cross-sections joined by a conical section B. 1, 2 and 3 are points on a line parallel to the axis of the conductor. The magnetic fields at 1, 2 and 3 have magnitudes B1, B2 and B3

(a) B1 = B2 = B3 

(b) B1 = B2 ≠ B3

(c) B1 < B2 < B3 

(d) B2 cannot be found unless the dimensions of the section B are known.

1 Answer

+1 vote
by (51.2k points)
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Best answer

Correct Answer is: (a) B1 = B2 = B3 

To find the magnetic field outside a thick conductor, the current may be assumed to flow along the axis. As points 1, 2, 3 are equidistant from the axis, B1 = B2 = B3.

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