Question

Equation of tangent of the circle x*2+y*2-8x-2y+12=0 at the points whose ordinates are 1

Answer 1

Kindly mention the absicsa too

Answer 2

Let the point on the circle be (x,1)Where the tangent is also passing from the same point.

x^{​​​​​​2}​​​​​+(1)²-8x-2(1)+12=0

x^{​​​​​​2}​​​​​-8x+11=0

Where x=-b+-√b²-4ac /2

x=4+-√5         

The equation of the tangents is x=4+√5 and x=4-√5