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If the function f(x) = x3 + ex/2 and g(x) = f-1(x), then the value of g′(1) is _____.

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Best answer

f(0) = 1, f'(x) = 3x2 + 1/2ex/2

⇒ f'[g(x)]g'(x) = 1

Put x = 0, we get

g'(1) = 1/f'(0) = 2.

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