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If y = tan^-1 4x/(1 + 5x^2) + tan^-1((2 + 3x)/(3 - 2x)), where 0 < x < 2/3 and dy/dx = λ/(1 + 25x^2), then find λ.

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If y = tan-1 4x/(1 + 5x2) + tan-1((2 + 3x)/(3 - 2x)), where 0 < x < 2/3 and dy/dx = λ/(1 + 25x2), then find λ.

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Therefore

dy/dx = 5/(1 + 25x2)

Hence, λ = 5

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