Question

The curve given by x + y =e^xy  has a tangent parallel to the y-axis at the point 

(A) (0, 1) 

(B) (1, 0) 

(C) (1, 1) 

(D) (−1, −1)

Answer 1

Answer is (B) (1, 0)

The curve is

x + y = e^xy

Differentiating with respect to x, we get

As tangent is parallel to y−axis.

Thus,

dy/dx = ∞ ⇒ 1 - xe^xy = 0 ⇒ 1 - x(x + y) = 0

This holds for x = 1, y = 0. 

Comments

Differentiate little more specifically plz