Correct option (B) There is a regular polygon with r/R = 2/3
Consider a regular polygon of n sides. Draw a line segment from its centre to each of its n sides to get n number of similar triangles which will look as shown in Fig.

Let θ be angle AOB. Therefore,
θ = 360°/n
Then from trigonometry of right triangles, we have

So we have,
r = a/2cot π/n
where a is the side of polygon. Therefore,
