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The value of ∫(lnx/(1 + lnx)^2)dx is equal to

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in Integrals calculus by (41.7k points)

The value of ∫(lnx/(1 + lnx)2)dx is equal to

(A) x/(1 - lnx) + c

(B) xlnx/(1 + lnx) + c

(C) x/(1 + lnx) + c

(D) lnx/(x + xlnx) + c

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Answer is (C) x/(1 + lnx) + c

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