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In the given compound the order of case with which hydrogen atom can be abstracted from carbons I to VI is :

(A) I > VI > IV = V > I > III 

(B) II > I > VI > III > IV = V 

(C) II > I > III > VI > IV = V 

(D) IV > II > I > III > IV = V

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Correct answer is (B) II > I > VI > III > IV = V

Breaking of C–H bond is inversely related to stability of intermediate free radical.

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