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A famous relation in physics relates 'moving mass' m to the 'rest mass' m0 of a particle in terms of its speed v and the speed of light c. A boy recalls the relation almost correctly but forgets where to put the constant c. He writes:

m = m0/(1-v2)1/2 Guess where to put the missing 'c'.

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On rearranging, we have m0/m =√(1-v2).

Since, the left hand side is dimensionless, so the right hand side should also be dimensionless.This will be so,if √(1-v2) is √(1 -v2/c2).

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