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The value of ∫ln((1 - tanx)/(1 + tan^2x))dx for x ∈ [0, π/4] is

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The value of  ∫ln((1 - tanx)/(1 + tan2x))dx for x ∈ [0, π/4] is

(A) (π/4)ln(1/2)

(B) (3π/8)ln2

(C) (π/8)ln2

(D) (-3π/8)ln2

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Answer is (D) (-3π/8)ln2

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