Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.9k views
in Integrals calculus by (41.7k points)

Sketch the region bounded by 3x + 4y ≤ 12.

1 Answer

+1 vote
by (41.5k points)
selected by
 
Best answer

Converting the inequality into equation we get 3x + 4y = 12. This line meets x-axis at (4, 0) and y-axis at (0, 3). Joining these two points we obtain the straight line represented by 3x + 4y = 12. This straight line divides the plane in two parts. One part contains the origin the other does not contain the origin. Clearly, (0, 0) satisfies the inequality 3x + 4y ≤ 12. So, the region represented by 3x + 4y ≤ 12 is the region containing the origin as shown in Fig.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...