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in Integrals calculus by (41.7k points)

Area common to the curves y2 = ax and x2 + y2 = 4ax is equal to

(A) (93 + 4π)a2/3

(B) (93 + 4π)a2

(C) (93 - 4π)a2/3

(D) None of these 

1 Answer

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by (41.4k points)
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Best answer

Answer is (D) None of these

See Fig.

y2 = ax, x2 + y2 - 4ax = 0 

y2 = 4ax - x2

x2 + ax – 4ax = 0

x2 - 3ax = 0

x(x - 3a) = 0

x = 0, x = 3a

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