Answer is (D) 9
First solving the equations, we have
2√x = x - 3 (1)
Squaring on both sides of Eq. (1), we get
4x = x2 - 6x + 9 ⇒ x2 - 10x + 9 ⇒ x = 9, x = 1
Since x = 1 intersects the parabola below the x-axis, this point is extraneous.
So, for x = 9 we have, y = 3.
Therefore, the required area under the curve (see Fig. 24.33) is
