Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
805 views
in Integrals calculus by (41.5k points)

In what ratio does the x-axis divide the area of the region bounded by the parabolas y = 4x - x2 and y = x2 - x.

1 Answer

+1 vote
by (41.7k points)
selected by
 
Best answer

See Fig. 

y = 4x - x2 = 4 - (x - 2)

Therefore, (x - 2)2 = -(y - 4) is a parabola with vertex at (2, 4) and upwards.

Again y = x2 - x = [x - 1/2]2 - 1/4

Therefore, (x - 1/2)2 = y + 1/4 is a parabola with vertex B at (1/2, - 1/4) and downwards.

The two parabolas intersect at O(0, 0) and A(5/2, 15/4).

Therefore, ratio = 121/24.1/6 = 121/4.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...