Answer is
General solution of dy/dx = y/x + ϕ(x/y) is
yln|cx| = x (1)
On differentiating y In |cx| = x, we get,
y x 1/|cx| . c + ln |cx|dy/dx = 1
⇒ y/x + x/y(dy/dx) = 1
Therefore,
x/y(dy/dx) = 1 - y/x ⇒ dy/dx = y/x - y2/x2 (2)
Now comparing with the given differential equation
ϕ(x/y) = y2/x2 = - (y/x)2 = - (1/(x/y))2