The number of ways can be given as follows:
2 bowlers and 9 other players = 4C2 x 9C9
3 bowlers and 8 other players = 4C3 x 9C8
4 bowlers and 7 other players = 4C4 x 9C7
Hence, required number of ways is 4C2 x 9C9 + 4C3 x 9C8 + 4C4 x 9C7
= 6 x 1 + 4 x 9 + 1 x 36 = 78