Question

If ((3x - 4)/(3x + 4)) = x + 2, x ≠ - 4/3, and ∫f(x)dx = Alog|1 - x| + Bx + c then the ordered pair (A, B) is equal to (where C is a constant of integration)

(A) (-8/3, 2/3)

(B) (8/3, -2/3)

(C) (8/3, 2/3)

(D) (-8/3, - 2/3)

Answer 1

Answer is (A) (-8/3, 2/3)

It is given that

∫f(x)dx = Alog|1 - x| + Bx + c

Differentiating w.r.t. x, we get

Therefore, the ordered pair (A, B) is equal to (-8/3, 2/3)