Question

ABCD is a parallelogram with vector AC = i - 2j + k and vector BD = - i + 2j - 5k. Area of this parallelogram is equal to

(A) √5/2 sq. units

(B) 2√5 sq. units

(C) 4√5 sq. units

(D) √5 sq. units

Answer 1

Answer is (B) 2√5 sq. units

Area vector of parallelogram is

Therefore, area of the parallelogram is

|4i + 2j| = 2√5 sq. units