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The equation of a trajectory of an oblique projectile is: y = √3x - gx^2/2

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The equation of a trajectory of an oblique projectile is:

y = √3x - gx2/2

What is the initial velocity and the angle of projection of the projectile ?

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1 Answer

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The path of a projectile is given by

y = (tanθ) x - gx2/2(u cosθ)2 

Comparing the given equation with the standard equation, we have,

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