Question

The velocity associated with a proton moving in a potential difference of 1000 v is 4.37 x 10⁵ ms^-1. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.

Answer 1

v = 4.37 x 10⁵ ms^-1

m = 0.1 kg

h = 6.626 x 10^-34 Js

λ = h/mv

or, λ = {6.626 x 10^-34}/{10^-1 x 4.37 x 10⁵}

or, λ = 6.626/4.37 x 10^-38 = 1.51 x 10^-38 m.