Question

Evaluate:∫log(1+tanx)dx for x→0,π/4.

Answer 1

⇒ \(I = \log2[x]_0^{\frac \pi 4} - I\)   [from Eq. (i)]

⇒ \(2I = \frac \pi 4\log_e 2\)

⇒ \(I = \frac \pi 8\log_e2\)

Answer 2

Let

=>I=π/8log2