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+1 vote
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For a > 0, let the curves C1 : y2 = ax and C2 : x2 = ay intersect at origin O and a point P. Let the line x = b(0 < b < a) intersect the chord OP and the x-axis at points Q and R, respectively. If the line x = b bisects the area bounded by the curves, C1 and C2, and the area of ΔOQR = 1/2, then 'a' satisfies the equation 

(1) x6 – 12x3 + 4 = 0

(2) x6 – 12x3 – 4 = 0 

(3) x6 + 6x3 – 4 = 0

(4) x6 – 6x3 + 4 = 0

2 Answers

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Best answer

Answer is (1) x6 – 12x3 + 4 = 0

+1 vote
by (58.5k points)

Answer is (1) x6 - 12x3 + 4 = 0

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