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Let [t] denote the greatest integer ≤ t and lim(x→0) x[4/x] = A. Then the function, f(x) = [x2]sin(πx) is discontinuous, when x is equal to:

(1) √(A + 5)

(2) √(A + 1)

(3) √A

(4) √(A + 21)

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Best answer

Answer is (2) √(A + 1)

In option 1, 3, 4 values are integer and Integral Multiple of  in sine is always zero.

∴ f(x) is disc. at (A + 1)

+1 vote
by (52.8k points)

Answer is (2) √(A + 1)

ƒ(x) = [x2]sin(πx) will be discontinuous at non integers

∴ x = √(A + 1) i.e √5

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