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If x = 2sinθ - sin2θ and y = 2cosθ - cos2θ, θ ∈ [0, 2π], then d^2y/dx^2 at θ = π is:

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If x = 2sinθ - sin2θ and y = 2cosθ - cos2θ, θ ∈ [0, 2π], then d2y/dx2 at θ = π is:

(1) 3/2

(2) - 3/4

(3) 3/4

(4) - 3/8

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2 Answers

+1 vote
by (52.7k points)

Answer is (4) - 3/8

+1 vote
by (58.5k points)

Answer is (4) - 3/8

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