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A particle moving with kinetic energy E has de Broglie wavelength λ. If energy ΔE is added to its energy, the wavelength become λ/2. Value of ΔE, is : 

(1) 2E

(2) E

(3) 3E

(4) 4E

2 Answers

+2 votes
by (36.6k points)
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Best answer

Answer is (3) 3E

Given, de-Broglie wavelength = h/√2mE = λ

Also,

+1 vote
by (52.1k points)

Answer is (3) 3E

= 4KEi – KEi = 3KE = 3E

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