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A wire of length L and mass per unit length 6.0 × 10–3 kgm–1 is put under tension of 540 N. Two consecutive frequencies that it resonates at are : 420 Hz and 490 Hz. Then L in meters is :

(1) 8.1 m

(2) 5.1 m

(3) 1.1 m

(4) 2.1 m 

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Best answer

The correct answer is (4) 2.1 m

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by (52.1k points)

Answer is (4) 2.1 m

Fundamental frequency = 490 – 420 = 70 Hz

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