Here we need the dimension of the LHS = dimension of RHL = L1
Also, the dimension of the argument of the trigonometric function
= dimensionless
(a) Dimension of the argument of the sine function
(T1/T1) = T0 = dimensionless.
Dimension of a = L1 = dimensions of y.
∴ This formula is dimensionally correct
(b) Dimension of the argument of the sine function
= [LT-1] [T1] = L1
∴ This formula is dimensionally incorrect
(c) Dimension of the argument of the sine function
= t/a = T/L = [L-1] [T1] Also,
dimension of (a/t) = L/T = LT-1 Clearly,
∴ This formula is dimensionally incorrect.
(d) Dimension of a√2 = L1 = dimension of y Dimension of the argument of the sine function
= dimension of the argument of the cosine function = 2π(t/T) = T1/T1
= T° = dimensionless.
∴ This formula is dimensionally correct.