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0 votes
8.1k views
in Mathematics by (55.0k points)

Prove the following

(i) 3sin(π/6)sec(π/3) - 4sin(5π/6)cot(π/4) = 1

(ii) sin2(π/6) + cos2(π/3) - tan2(π/4) = - 1/2

(iii) 2sin2(π/6) + cos2(7π/6)cos2(π/3) = 3/2

(iv) 2sin2(3π/4) + 2cos2(π/4) + 2sec2(π/3) = 10

(v) cot2(π/6) + cos(5π/6) + 3tan2(π/6) = 6

1 Answer

+1 vote
by (52.7k points)
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Best answer

= 3 + cosec(π/6) + 1)

= 4 + 2 = 6

= RHS

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