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Find ∫sin2x cos3x dx

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Find ∫sin2x cos3x dx

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W.K.T sin x cosy = [sin(x + y) +sin(x – y)] 

Then ∫sin2x cos 3x dx = 1/2[∫sin 5x dx - ∫sinx dx]

= 1/2[1/5 cos 5x + cos x] + c

= -1/10 cos 5x + 1/2 cos x + c

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